Product Handbook 2026 - Volume 2

1.16

p Pm r

p

r

C V

=

= 1.16

C V

F L Pipeline ancillaries Ball valves 

C V = 10

P

31

Simplified equations for sizing (K v values = C v x 0.86)

1.16

p Pm r

C V

=

C V

=

F L

865 

P

pr

C V =

13

For steam and gases

Sub-critical flow

Critical flow

Where:

C V

=

C V

=

C V =

865

F L

pr

Pm

C V = Flow coeffecient of the valve F L = Pressure recovery factor pr = Specific density of gas (air = 1)

865 

P

pr

11

When:  P < 0.5 F L

When:  P > 0.5 F L

2 P

2 P

1

1

C V

=

p

T

r

C V =

865

F L

pr

Pm

C V

=

P 1 = Upstream pressure (bar a) P 2 = Downstream presure (bar a) T = Inlet temperature in °K (°C + 273) = Flowrate of gas in Nm³/h (at 15°C and 1 bar a) = Flowrate of gas in in kg/h T SO = Superheating of steam in °C 2 When P ≤ v 2 1 When P V P P use Pm= P - 0.96- 0.28 ≤ v  2 When P ≤ v 2 1 When P V P P use Pm= P - 0.96- 0.28 ≤       v  P C 2 When P ≤ v C V p = 1.16 r 

P 1

295

2 - P

2

For gases (volumetric flowrate)

For gases (volumetric flowrate) 2

T

  

  

P V P C P V P C

P use Pm= P - 0.96- 0.28 

P V

C V =

1

360 (P 1

2 - P

2 )pr

p

T

r

p F L P 1 r

T

2

C V =

C V

=

T

  

  

C V C V = = C V = C V =

P 1 P V P C

295 P use Pm= P - 0.96- 0.28 P use Pm= P - 0.96- 0.28  1 

2 - P

257

2 P V

2

360 (P 1 360 (P 1

T 2 - P

2 )pr

  

  

2

P V

T

1

P V P V

C V =

2 - P

2 )pr

T 311F L P 1 pr T 311F L P 1 pr T 311F L P 1 pr 13.81 P 1 2 - P

2

C V For gases (mass flowrate) p F L P 1 r T 360 (P 1 = 257 360 (P 1

T 2 - P

2 )pr

     

     

For gases (mass flowrate)

2

P V P C P r P P C r p  p  

2 - P

2 )pr

C V = C V = C V T (Temperature of superheated steam - Temperature of saturated steam) S = Flowrate of steam in kg/h 2 Note: These equations are only a simplified version of the original sizing equations of the ISA and IEC regulations. The results are sufficiently close for practical use. There could be a maximum error of 8% in the transition of non-choked flowrate to choked flowrate. 360 (P 1 360 (P 1  2 - P 2 - P P 2 2 )pr 2 )pr T r P 2 = 1.16 P 1 When C V P use Pm= P - 0.96- 0.28  P V ≤ v p = 1.16 r C V = 1.16 = 1.16 1.16 C V F L p Pm r = 1.16 F L  p  = 1.16 1.16 F L 1.16 C V C V p Pm r = 1.16  p r =  C V F L p Pm r = C V P = pr 865  P 

2

C V =

T

C V = C V = C V =

C V = =

360 (P 1 T 311F L P 1 pr 2 - P T 311F L P 1 pr T 311F L P 1 pr 13.81

C V

  

P V P C

2 )pr

  

P V P C

P V

2

2

8

P V

2

=

C V

13.81 13.81 11.95 11.95 11.95

P 1

2 - P

2

p Pm r p Pm r p Pm r pr

2

For saturated steam

C V V = For saturated steam =

C V C V C V

T

F

P 1 L P 1

2 - P

C V = C V =

2

2

P 1 P 1

2 - P

2

T 311F L P 1 pr F L 

60 (P 1

2 - P 2

2 )pr 2

=

T 311F L P 1 pr

2

C V

=

C V = C V =

2

C V

=

1

2

C V

=

865  865 

P

pr

F L P 1

13.81

2 - P

2

F L P 1 (1 + 0.00126 T SO ) 13.81 P 1 (1 + 0.00126 T SO ) 13.81 P 1 (1 + 0.00126 T SO ) 13.81 2 - P (1 + 0.00126 T SO ) 11.95 F L P 1 2 2 (1 + 0.00126 T SO ) 11.95 F L P 1 (1 + 0.00126 T SO ) 11.95 F L P 1 2 - P 2 2 P 1 2 - P 2 2

2

C V V

=

=

C V

=

C V

1.16

P pr F L

pr Pm 

C V C V C V C V C V C V

= =

= = =

C V C V C V C V C V C V

865 

P

13.81 11.95 11.95

P 1 F L P 1 F L P 1

F L

T 11F L P 1 pr L 1

=

2 - P

C V

=

2

2 For superheated steam

For superheated steam

=

C V

C V

=

865 

2 - P 2 - P pr P

865

F L

pr

Pm

=

C V

13.81 13.81

P 1

2

P 1

2

C V

=

2

F L P 1 (1 + 0.00126 T SO ) 13.81 P 1 (1 + 0.00126 T SO ) 13.81 (1 + 0.00126 T SO ) 11.95 F L P 1 2 - P 11.95 F L P 1 2 2 (1 + 0.00126 T SO ) 11.95 F L P 1 P 1 P 1 2 - P 2 2 2 - P (1 + 0.00126 T SO ) 13.81 2 2

2

=

C V C V =

865

F L

pr

Pm

= = =

p

T

r

= = =

865

F L

pr

Pm

C V

=

P 1

295

2 - P

2

865 

P

pr

11.95

2

=

C V

11.95 11.95 865

pr

Pm

=

C V

F L P 1 F L P 1 L

p

T

r

C V =

3.81

P 1 1

2 - P 2

2

C V

2

=

2

2

P 1

295

p 2 - P T

2

r T

2

C V =

P 1 p F L P 1 p F L P 1 r r

C V

C V C V C V

= =

7.3.110

=

p

T

r

=

C V

295

2 - P

=

C V

2

P 1 (1 + 0.00126 T SO ) 13.81 (1 + 0.00126 T SO ) 13.81 2 - P 2 - P 2 2 P 1 2 2 pr 2 - P F L Pm 865  p P 1 P 1 2 - P 2 2 T 295 r 2 2 295 (1 + 0.00126 T SO ) 11.95 F L P 1 (1 + 0.00126 T SO ) 11.95 F L P 1 P 1 2 - P 2 2 p F L P 1 T r p p F L P 1 r T 295 257 257 r T

257

2

=

C V

=

C V

F L P 1 1.95 L 1

C V =

T

=

=

C V

257

p F L P 1 r

T

=

C V

257

P 1 2 (1 + 0.00126 T SO ) 13.81 2 - P 2 2 2 )

C V =

= = =

C V V

C V = C V = C V

1

2

p F L P 1 r

T

(1 + 0.00126 T SO ) 11.95 F L P 1 )

=

C V

257

L 1

10.3 95

TI-P133-46 CMGT Issue 2

Page 3 of 4

M15 ISO Ball Valve for Control of Fluids - Sizing Sheet

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